Implement furthest element computation
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@ -1,16 +1,8 @@
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from preprocessing import parse_file
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from pandas import DataFrame, Series
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from pandas import DataFrame
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from sys import argv
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def get_furthest_element(element, data):
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element_df = data.query(f"source == {element} or destination == {element}")
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furthest_index = element_df["distance"].idxmax()
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furthest_row = data.iloc[furthest_index]
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print(furthest_row)
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return furthest_row
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def get_first_solution(n, data):
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distance_sum = DataFrame(columns=["point", "distance"])
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for element in range(n):
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@ -24,16 +16,33 @@ def get_first_solution(n, data):
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return furthest_row
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def get_different_element(original, row):
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if row.source == original:
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return row.destination
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return row.source
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def get_furthest_element(element, data):
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element_df = data.query(f"source == {element} or destination == {element}")
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furthest_index = element_df["distance"].idxmax()
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furthest_row = data.iloc[furthest_index]
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furthest_point = get_different_element(original=element, row=furthest_row)
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return {"point": furthest_point, "distance": furthest_row["distance"]}
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def greedy_algorithm(n, m, data):
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solutions = DataFrame(columns=["point", "distance"])
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first_solution = get_first_solution(n, data)
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solutions = solutions.append(first_solution, ignore_index=True)
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for _ in range(m):
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centroid = solutions.apply(get_furthest_element, 1, data)
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solutions = solutions.append(centroid)
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last_solution = solutions["point"].tail(n=1)
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centroid = get_furthest_element(element=int(last_solution), data=data)
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solutions = solutions.append(dict(centroid), ignore_index=True)
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data = data.drop(centroid["point"], columns=["source", "destination"])
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print(solutions)
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# NOTE In each step, switch the element that gives the least amount
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# NOTE In each step, switch to the element that gives the least amount
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def local_search():
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pass
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